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| General Programming General NinjaScript programming questions. |
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05-19-2007, 02:54 AM
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#1 |
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Senior Member
Join Date: Jan 2006
Location: Margate, Florida, USA
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Slope()...
Thanks for the Slope(). Please explain this. My 2 studies are clearly pointing up for currentbar and previous bar. However, as you can see, my readout is showing a negative number. Why? (see attached)
My code: slowLine = Slope(CCI(14), 1, 0); fastLine = Slope(CCI(6), 1, 0); I tried Slope(CCI(14), CurrentBar-1, 0); But got some really funky output. A very large number. I just want the slope from previous bar to current bar. BTW, what is your formula for the calc'ing of Slope();?
Last edited by funk101; 05-19-2007 at 01:36 PM.
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05-19-2007, 04:51 PM
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#2 |
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Administrator
Join Date: Nov 2004
Location: Denver, CO, USA
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Forumula was incorrect. Here is what I am changing it to for the next update. Thanks for pointing this out. I had endBar - startBar, which is correct if the parameters passed in were absolute bar numbers which they are not. They reference the number of bars ago.
return (series[endBar] - series[startBar]) / (startBar - endBar);
Ray
NinjaTrader Customer Service |
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05-19-2007, 05:11 PM
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#3 |
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Senior Member
Join Date: Jan 2006
Location: Margate, Florida, USA
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Ah!
Whew! I thought it was me. Glad I could be of service.
 Thanks, let me know when the update is available.
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05-26-2007, 05:40 PM
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#4 |
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Any idea when we'll have the updated slope() method available? I'm unable to edit the indicator because I can't see it.
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05-26-2007, 06:01 PM
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#5 |
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Administrator
Join Date: Nov 2004
Location: Denver, CO, USA
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Likely end of this coming week.
Ray
NinjaTrader Customer Service |
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06-16-2007, 09:39 AM
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#6 |
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Bump any date on the update?
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