Help to simplify some code

[GeorgeW]

Hello,
I am trying to include a condition into a code whereby Close[0] would be greater than the first Close going backwards that is greater than Close[3] and occurs before Close[3]. I don’t think I can use Most Recent Occurrence (MRO) to do this, as that works back from Close[0] as far as I understand, and so may pick up Close[1] or Close[2]. Currently the code would look something like this:

if ((Close[4] > Close[3] && Close[0] > Close[4]) ||  (Close[5] > Close[3] && Close[0] > Close[5]))

In order to catch the first Close > Close[3] I would need to keep repeating this condition, Close[6] next, until I was satisfied I had included enough bars prior to Close[3] to catch one where the Close > Close[3].

Is there an easier way of doing this? Any help would be much appreciated.

Thank you.

[JerryWar]

GeorgeW
Is CalculateOnBarClose = True ?

[NinjaTrader_ChelseaB]

Hello GeorgeW,

Are you trying to compare an arbitrary number of bars based on a variable?

You could use a for loop and compare the current index with the previous index (starting with 1 in the loop).

https://www.dotnetperls.com/for

[GeorgeW]

Thanks for your responses JerryWar and ChelseaB.

CalculateOnBarClose = true yes.

I am trying to compare the close of an arbitrary number of bars before bar[3] to Close[3], and then the first one that I pick up that is greater than Close[3] is then compared to Close[0]. I will try the for loop.

[JerryWar]

George ,
I think there is a flaw in your statement. ergo. If you were to code it exactly as you wrote that
statement , I don't think you would get what your looking for.
You said " then the first one that I pick up that is greater than Close[3] " . Since you are using Calculate on BarClose= true. That bar will be Close[0] . You then went on to say " is then compared to Close[0]" but that bar already is Close[0] so it will be ==

Hope this helps
Jerry.

[GeorgeW]

Hello JerryWar,

I am working back from 3 reversal bars and the last climax bar. So counting back from the 3rd reversal bar, which is Close[0], the climax bar becomes Close[3], I then want to compare Close[0], the third reversal bar, to the first close before Close[3] that exceeds Close[3]. As I have written the code, the signals are appear on the 3rd reversal bar, as intended, and sometimes the 4th (because this meets the condition for a 3rd reversal bar).

[lhthe]

Are you trying to compare an arbitrary number of bars based on a variable?

[GeorgeW]

Are you trying to compare an arbitrary number of bars based on a variable?

Hello lhthe,
I am not sure I understand the question correctly. But if any of a number of bars prior to bar[3] could be the first to exceed it, then I suppose I am comparing the close of an arbitrary number of bars to Close[3], and then once I find the first bar whose close exceeds it, I am then comparing that close to Close[0].