fillrectangle gradient

[keepsimple]

hi,

i am trying to fill a rectangle in onrender with a lineargradientbrush, how whould I do that?

thanks in advance

[NinjaTrader_Jesse]

Hello,

Thank you for the question.

Below is an example using LinearGradientBrush:

SharpDX.Direct2D1.LinearGradientBrush      linearGradientBrush = new SharpDX.Direct2D1.LinearGradientBrush(RenderTarget, new SharpDX.Direct2D1.LinearGradientBrushProperties()
{
	StartPoint = new SharpDX.Vector2(50, 0),
	EndPoint = new SharpDX. Vector2(450, 0),
},
new 	SharpDX.Direct2D1.GradientStopCollection(RenderTarget, new SharpDX.Direct2D1.GradientStop[]
{
	new	SharpDX.Direct2D1. GradientStop()
	{
		Color = SharpDX.Color.Blue,
		Position = 0,
	},
	new 	SharpDX.Direct2D1. GradientStop()
	{
		Color = SharpDX.Color.Green,
		Position = 1,
	}
}));

RenderTarget.FillRectangle(new SharpDX.RectangleF(100, 100, 450, 150), linearGradientBrush);

I look forward to being of further assistance.

[keepsimple]

Thanks, Jesse

thats what I was looking for, one additional question, do I have to "freeze" the brush, when I use this?
P.S. What do the values in the Brackets in the vector2 definition exactly stand for?

[NinjaTrader_Jesse]

Hello,

In this case I do not believe there is a need or way to do so. This is a SharpDX.Direct2D1.LinearGradientBrush opposed to a System.Windows.Media.LinearGradientBrush

It is always good practice to freeze/dispose of objects you create explicitly to ensure they are marked for removal correctly. SharpDX.Direct2D1.LinearGradientBrush specifically has no Freeze() method.

Regarding the second question, if you are asking about: Vector2(50, 0), or the (50,0). A Vector2 contains a 2 dimension coordinate or X and Y so this would be 50 X and 0 Y.

I look forward to being of further assistance.

[keepsimple]

thanks jesse,

will work with that, asking about the vector2 I knew it stands for coordinates, perhaps I formulated my question a little confusing, I wanted to know, for what those coordinates are needed, I played a little with it and i think they determine the start and endpoint for the coloring. hope thats right.

thanks again for your help.

regards

[NinjaTrader_Jesse]

Hello,

Thank you for clairifing.

Yes those coordinates go along with the coords you see in the RenderTarget command regarding the colors position:

StartPoint = new SharpDX.Vector2(50, 0),
EndPoint = new SharpDX. Vector2(450, 0),

FillRectangle(new SharpDX.RectangleF(100, 100, 450, 150)

This would be a Horizontal gradient as the Start is 50 X and end is 450 X with 0 Y on both.

For a Vertical you could use something like:

StartPoint = new SharpDX.Vector2(0, 150),
EndPoint = new SharpDX. Vector2(0, 250),

It appears that this may be the RenderTarget coordinates in these Vectors, as 0Y through 150 Y would produce a solid color where 150 through 250 produces a gradient as the Rectangle starts at 100 Y.

I look forward to being of further assistance.

[kkc2015]

Jesse,
On the code below, how do you transform Color11 so that it can be accepted by Color (inside GradientStop). The objective is to change Color based on opacity.
SharpDX.ColorBGRA Color11 = new SharpDX.ColorBGRA(0f, 1f, 0f, 0.5f);

new SharpDX.Direct2D1. GradientStop()
{
Color = SharpDX.Color.Blue,
Position = 0,
},

[NinjaTrader_Jesse]

Hello,

They Type of color this takes as an input is a Color4, 4 meaning it has 4 overloads for values it can take (R G B A)

Here is a simple example of constructing a new Color4 object:

SharpDX.Color4 color = new SharpDX.Color4(100,100,100,255);

Color = SharpDX.Color.Blue,

would instead be

Color = color,

I look forward to being of further assistance.

[kkc2015]

Thank you very much. SharpDX.Color4 is accepted by Color (inside GradientStop).