eg Math.Max(n1,n2,n3,.....n) - obviously Math.Max only takes 2 arguments and I am looking to analyse more than that.
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You could do Math.Max(Math.Max(___, ____), ___) and cascade it. If you have a ton of values you could create a DataSeries and use MAX(myDataSeries, 20)[0] to get the max value of the last 20 values. You could also just create a loop to go through Math.Max against your list, storing the higher value each time and returning the max at the end.Josh P.NinjaTrader Customer Service
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Thanks Josh - I shall try and use either of those methods and see if I can get it to work. I only have 3 arguments so it shouldn't be too onerous.
If I call a function like MAX is it much more cpu intensive than writing say a nested Math.Max set of functions ( say 2)?
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