double printed like an integer

[jrbolsa]

Hi again, almost finishing this indicator

Look at this code:
double mydouble;
mydouble=5/3;
Print(mydouble);
mydouble=5.3/3.3;
Print(mydouble);

results:
1
1,66666666666667

question:
How can i obtain the last result making the division between two integers (5/3)?
I hope not to declare
double mydouble=0.0;
because i'm really speaking about a matrix:
private double [] mydouble = new double[10000];
and I don't know how to initialize it (i expect not with a for or while for each element)

thanks,
jr.

[jrbolsa]

excuse me:
not 5.3/3.3

i meant:
5.0/3.0

[Ralph]

Hi jr,

Math.Floor returns the integer part of a double:
Math.Floor(5.0/3.0) -> 1.0

Regards
Ralph

[jrbolsa]

I'm afraid I didn't explain correctly.
What I need is:
5/3 -> 1,66666666666667

5 -> integer
3 -> integer
result -> double

thank you so much,
jr.

[Ralph]

I didn't read your post correctly. You have to convert at least one variable to double prior to application, there is no other way around:

double dblVal = 5;
int intVal = 3;
double mydouble = dblVal / intVal;

I expect 1.6666 as the result.
You could give it a try, I didn't test it.

Regards
Ralph

[jrbolsa]

You're right, but I can't define the variables like double (I should change many lines). Isn't there any conversion, something like math.todouble(int) or something like that?

[Ralph]

Still not sure, how you do apply the integers troughout your code. You could convert integers before usage with a type cast:

int int5= 5;
int int3 =3;
double mydouble = (double)int5 / int3;

Regards
Ralph

[jrbolsa]

Fixed. I was mistaken. I could change the variables affected. Only nine. I declared them double and works ok.

thank you so much
jr.